某网络拓扑结构如下:在路由器R2上采用show ip rout命令得到如下所示结果。 R2> ... R 192.168.2.0/24[120/1] via 61.114.112.1,00:00:11,Serial2/0 C 192.168.1.0/24 is directly connected,FastEthernet0/0 61.114.112.0/30 is subnetted,1 subnets C 61.114.112.0 is directly connected,Serial2/0 R2> 则host1可能的IP地址为(),路由器R1的S2/0口的IP地址为()。 A.192.168.2.1B.192.168.1.1C.61.114.112.1D.61.114.112.2A.192.168.2.1B.192.168.1.1C.61.114.112.1D.61.114.112.2 请帮忙给出正确答案和分析,谢谢!